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Which values of m and b will create a system of equations with no solution? Select two options. y = mx + b y = –2x + A system of equations. y equals m x plus b. y equals negative 2 x plus StartFraction 3 over 2 EndFraction. A coordinate grid with a line labeled y equals negative 2 x plus StartFraction 3 over 2 EndFraction and passes through the points (9, 1.5) and (1, 0.5). m = –3 and b = m equals negative 3 and b equals negative StartFraction 2 over 3 EndFraction. m = –2 and b = m equals negative 3 and b equals negative StartFraction 1 over 3 EndFraction. m = 2 and b = m equals 2 and b equals negative StartFraction 2 over 3 EndFraction. m = m equals StartFraction 3 over 2 EndFraction and b equals negative StartFraction 2 over 3 EndFraction and b = m equals negative StartFraction 3 over 2 EndFraction and b equals negative StartFraction 2 over 3 EndFraction m = -2 and b = m equals negative 2 and b equals negative StartFraction 2 over 3 EndFraction

Which values of m and b will create a system of equations with no solution Select two options y mx b y 2x A system of equations y equals m x plus b y equals neg class=
Which values of m and b will create a system of equations with no solution Select two options y mx b y 2x A system of equations y equals m x plus b y equals neg class=
Which values of m and b will create a system of equations with no solution Select two options y mx b y 2x A system of equations y equals m x plus b y equals neg class=

Respuesta :

Answer:

m = -2 and b = -1/3

m = -2 and b = -2/3.

Step-by-step explanation:

y = -2x - 1/3

y = -2x - 2/3

This system has no solutions because y cannot be 2 different values at once.

profantoniofonte

Answer:

B, E

Step-by-step explanation:

Given the first function:

[tex]y=-2x+\frac{2}{3}[/tex]

A Linear System with no solutions is graphically represented by two parallel lines, therefore with the same slope. So in this case, m has to be equal to -2.

And to this inconsistent system, if the linear parameter is not so relevant. So if m=-2 then b may be either equal to -1/3 or -2/3 according to the options.

Given the alternatives

No Solution System:

[tex]\left\{\begin{matrix}y=-2x+\frac{2}{3} & \\ y=-2x-\frac{1}{3} & \end{matrix}\right.[/tex]

Or

[tex]\left\{\begin{matrix}y=-2x+\frac{2}{3} & \\ y=-2x-\frac{2}{3} & \end{matrix}\right.[/tex]

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