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How much resistance does led bulb in a 4.5 volt flashlight provide if it draws .05 amps of current

Respuesta :

MathPhys

Answer:

90 Ω

Explanation:

Ohm's law states voltage is the product of current and resistance:

V = IR

Given V = 4.5 V and I = 0.05 A:

4.5 V = (0.05 A) R

R = 90 Ω

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