Answer:
The answer to your question is: 15 m/s2
Explanation:
Equation x = at3 - bt2 + ct
a = 4.1 m/s3
b = 2.2 m/s2
c = 1.7 m/s
First we find x at t = 4.1 s
x = 4.1(4.1)3 - 2.2(4.1)2 + 1.7(4.1)
x = 4.1(68.921) - 2.2(16.81) + 6.97
x = 282.58 - 36.98 + 6.98
x = 252.58 m
Now we find speed
v = x/t = 252.58/ 4.1 = 61.6 m/s
Finally
acceleration = v/t = 61.6/4.1 = 15 m/s2
The acceleration of the object is the change in the velocity of the object within given time interval.
The acceleration of the object at time t = 4.1 seconds is 15.26 m/s2.
Given that the position of an object is x = at3 - bt2 + ct, where a = 4.1 m/s3, b = 2.2 m/s2, c = 1.7 m/s.
The position of the object at time t = 4.1 s is calculated as given below.
[tex]x = at^3-bt^2+ct\\[/tex]
[tex]x = 4.1\times (4.1)^3 - 2.2 \times (4.1)^2 + 1.7\times 4.1[/tex]
[tex]x = 252.56\;\rm m[/tex]
The velocity v of the object at time t = 4.1 s is given below.
[tex]v = \dfrac{x}{t}[/tex]
[tex]v = \dfrac {252.56}{4.1}[/tex]
[tex]v = 62.67\;\rm m/s[/tex]
The acceleration of the object at time t =4.1 s is given below.
[tex]a = \dfrac {v}{t}[/tex]
[tex]a = \dfrac {62.67}{4.1}[/tex]
[tex]a = 15.26\;\rm m/s^2[/tex]
Hence we can conclude that the acceleration of the object at time t = 4.1 seconds is 15.26 m/s2.
To know more about the acceleration, follow the link given below.
https://brainly.com/question/12134554.
