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Two spheres have volumes of 8r cm3 and 64st cm3. If the surface area of the smaller sphere is 16 t cmwhat is thesurface area of the larger sphere?o 641 cm2o 96T cm128 cm2561T cm

Two spheres have volumes of 8r cm3 and 64st cm3 If the surface area of the smaller sphere is 16 t cmwhat is thesurface area of the larger sphereo 641 cm2o 96T c class=

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apologiabiology
well

V=(4/3)pir^2
SA=4pir^2

we don't need the SA of smaller sphere wh cares

larger sphere, solve for pir

larger sphereV=64pi
V=(4/3)pir^3
64pi=(4/3)pir^3
multiply both sides by 3/4 to clea fraction
48pi=pir^3
divide both sides by pi
48=r^3
cube root both sides
2∛6=r

sub back

SA=4pir^2
r=2∛6
SA=4pi2∛6^2
SA=4pi4∛36
SA=16∛36pi
aprox
52.83pi

SA=52.83pi cm^2
what is wrong with the computer systems? the answer is never listed and why do they have to give you the surface area of the smaller one

I hope the answer is not "oh, 8pi times 2=16pi, so 64pi times 2=128pi"


answer is not listed
I don't know what's happening to the math system

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