Answer:
[tex]2.55\times 10^{6}g[/tex] Cu can be obtained from [tex]7.35\times 10^{3}kg[/tex] ore
Explanation:
1 kg = 1000 g
So, mass of ore is [tex](7.35\times 10^{3}\times 1000)g[/tex] = [tex]7.35\times 10^{6}g[/tex]
Now, 100 g of ore contains 34.63 g of Cu
So, [tex]7.35\times 10^{6}g[/tex] ore contains [tex]\frac{(34.63g)\times (7.35\times 10^{6}g)}{100g}[/tex] Cu or [tex]2.55\times 10^{6}g[/tex] Cu.