Answer:
The current pass through the coil is 6.25 A
Explanation:
Given that,
Diameter = 25 cm
Magnetic field = 1.0 mT
Number of turns = 100
We need to calculate the current
Using the formula of magnetic field
[tex]B =\dfrac{\mu_{0}NI}{2\pi r}[/tex]
[tex]I=\dfrac{B\times2\pi r}{\mu N}[/tex]
Where, N = number of turns
r = radius
I = current
Put the value into the formula
[tex]I=\dfrac{1.0\times10^{-3}\times2\pi\times12.5\times10^{-2}}{4\pi\times10^{-7}100}[/tex]
[tex]I=6.25\ A[/tex]
Hence, The current passes through the coil is 6.25 A
