Answer: 0.4404
Step-by-step explanation:
Let the random variable x is normally distributed .
Given : Mean : [tex]\mu=\ 87[/tex]
Standard deviation : [tex]\sigma= 55[/tex]
The formula to calculate the z-score :-
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x = 79
[tex]z=\dfrac{79-87}{55}\approx-0.15[/tex]
The p-value = [tex]P(x<79)=P(z<-0.15)[/tex]
[tex]=0.4403823\approx0.4404[/tex]
Hence, the required probability : [tex]P(x<79)=0.4404[/tex]
