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If you know that the change in entropy of a system where heat was added is 12 J/K, and that the temperature of the system is 250 K, what is the amount of heat added to the system? a)-5J b)-125J c)- 600 J d)-5000 J e)-8000 J

Respuesta :

Solution:

Given:

Change in entropy of the system, ΔS = 12J/K

Temperature of the system, [tex]T_{o}[/tex] = 250K

Now, we know that the change in entropy of a system is given by the formula:

ΔS = [tex]\frac{\Delta Q}{T_{o}}[/tex]

Amount of heat added, ΔQ = [tex]\Delta S\times T_{o}[/tex]

ΔQ = 3000J

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