Answer:
276.5 m/s^2
Explanation:
The initial angular velocity of the turbine is
[tex]\omega=0.626 rev/s \cdot 2\pi rad/rev =3.93 rad/s[/tex]
The length of the blade is
r = 17.9 m
So the centripetal acceleration is given by
[tex]a=\omega^2 r[/tex]
At the instant t = 0,
[tex]\omega=3.93 rad/s[/tex]
So the centripetal acceleration of the tip of the blades is
[tex]a=(3.93 rad/s)^2 (17.9 m)=276.5 m/s^2[/tex]
