Respuesta :
Answer:
Option B [tex]HI=5\sqrt{2}\ units[/tex]
Step-by-step explanation:
Applying the Pythagoras Theorem
[tex]HI^{2}=(y2-y1)^{2}+(x2-x1)^{2}[/tex]
substitute the given values
[tex]HI^{2}=(2+3)^{2}+(3+2)^{2}[/tex]
[tex]HI^{2}=(5)^{2}+(5)^{2}[/tex]
[tex]HI^{2}=50[/tex]
[tex]HI=5\sqrt{2}\ units[/tex]