in the diagram AC is a diameter of circle o if the slope of BC is -1/2 what is the slope of a b

Answer:
Step-by-step explanation:
We have a circle described on the triangle. If one side of the triangle is the diameter of the circle, then the triangle is the right triangle.
Therefore m∠B = 90°.
AB is perpendicular to BC.
Let
k: y = m₁x + b₁ and l: y = m₂x + b₂
l ⊥ k ⇔ m₁m₂ = -1 ⇒ m₂ = - 1/m₁
We have the slope of BC m₁ = - 1/2.
Therefore the slope of AB m₂ = - 1/(- 1/2) = 2
The slope of AB is 2.
The general equation of a line is y = mx + c
where m is the slope of the line and c is the intercept.
Slope of line is defined as the angle of line. It is denoted by m
Slope m = (y₂ - y₁)/(x₂ -x₁ )
Consider two points on a line—Point 1 and Point 2. Point 1 has coordinates (x₁,y₁) and Point 2 has coordinates (x₂, y₂)
We have a circle described on the triangle.
A triangle is said to be a right triangle if one of its sides corresponds to the circle's diameter.
Therefore m∠B = 90°.
AB is perpendicular to BC.
Let the system of two lines
line 1 as y = m₁x + c₁ and
line 2 y = m₂x +c₂
Here line 1 perpendicular to line 2
So m₁m₂ = -1 ⇒ m₂ = - 1/m₁
The slope of BC m₁ = - 1/2.
So the slope of AB m₂ = - 1/(- 1/2) = 2
Hence, the slope of AB is 2.
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