Answer:
37.9 kJ
Explanation:
We can calculate the thermal energy gained by the iron using the formula:
[tex]Q=m C_s \Delta T[/tex]
where
m = 35 g is the mass of the iron
Cs = 0.450 j/g is the iron's specific heat capacity
[tex]\Delta T= 2425 C - 20 C = 2405 C[/tex] is the change in temperature of the iron (assuming that the room's temperature is 20 C degrees)
Substituting numbers into the formula, we find
[tex]Q=(35 g)(0.450 J/g)(2405 C)=3.79\cdot 10^4 J=37.9 kJ[/tex]
