Answer:
A'(3/2, -9/4)
B'(-3, 9/4)
C'(3/2, 9/4)
Step-by-step explanation:
1. You have the following coordinates of the vertices of the triangle ABC:
A(-2,3), B(4,-3), C(-2,-3)
2. Therefore, to know the coordinates of the vertices of the trianle A'B'C' you must multiply each coordinate of the original triangle by the scale factor given in the problem (-3/4).
3. Then, you have:
[tex]A'=((-2)(-3/4)\ ,3(-3/4))=(3/2\ ,-9/4)[/tex]
[tex]B'=((4)(-3/4)\ ,(-3)(-3/4))=(-3\ ,9/4)[/tex]
[tex]C'=((-2)(-3/4)\ ,(-3)(-3/4))=(3/2\ ,9/4)[/tex]
