Please help! ASAP!!!

[tex]\boxed{x=13}[/tex]
The given equation represents a straight line:
[tex]y+2=-\frac{4}{5}(x-8)[/tex]
To find the missing value, we need to isolate the variable x as follows:
[tex]y+2=-\frac{4}{5}(x-8) \\ \\ \therefore \frac{5}{4}(y+2)=-(x-8) \\ \\ \therefore \frac{5}{4}(y+2)=-x+8 \\ \\ \therefore x=8-\frac{5}{4}(y+2)\\ \\ So: \\ \\ If \ y=-6 \ then: \\ \\ \boxed{x=13}[/tex]