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Sodium Oxide (Na2O) can react with hydrochloric acid (HCl) to produce sodium chloride (NaCl) and water (H2O) according to the following equation: Na2O + 2HCl -> 2NaCl + H2O How many total atoms are present before and after the reaction? A) 2 before and 2 after
B) 3 before and 3 after
C) 5 before and 5 after
D) 7 before and 7 after

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znk

Answer:

D) 7 before and 7 after

Step-by-step explanation:

  Na₂O   +  2HCl    ⟶    2NaCl      +   H₂O

3 atoms + 4 atoms ⟶ 2×2 atoms + 3 atoms

        7 atoms         ⟶    4 atoms   + 3 atoms

        7 atoms         ⟶            7 atoms

There are seven atoms present before and after the reaction.


gavergan

The answer is D) 7 before and 7 after

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