alexisnridenour
contestada

Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. If two heterozygous individuals with polka-dot tails mate, what's the probability of the phenotype and genotype combinations of the offspring?
A. 50 percent chance of a polka-dot tail and 50 percent chance of a solid colored tail (50 percent PP; 50 percent pp)
B. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (75 percent Pp; 25 percent pp)
C. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (25 percent PP; 50 percent Pp; 25
percent pp)
D. 25 percent chance of a polka-dot tail and 75 percent chance of a solid colored tail (25 percent PP; 50 percent Pp; 25
percent pp)

Respuesta :

AlexaK61301
Make a punnett square. The individuals are heretozygus (different) so their genotype is Pp.
P p
_______
P | PP | Pp |
_______
p | Pp | pp |
_______

There is...
Genotype (genetics)
25% chance homozygus polkadot. (PP)
25% chance homozygus solid (pp)
50% chance heterozygus polkadot. (Pp)

Phenotype (physical trait)
75% chance polkadot
25% chance solid.

The answer: C


*sorry the punnett square is so weird looking :) i hope this was helpful.


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