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identifying equation in point slope form for the line parallel to Y=1/2x-7 that passes through (-3,-2)

Respuesta :

debmommabear

Answer:

(y+2)=1/2(x+3)

Step-by-step explanation:

y-y1 = m (x-x1)  m=1/2, x1= -3, y1= -2

Answer:

[tex]y+2=\frac{1}{2}(x+3)[/tex]

Step-by-step explanation:

point slope form for the line parallel to [tex]y=\frac{1}{2}x-7[/tex] that passes through (-3,-2)

First find the slope of the given line

Given line is in the form of [tex]y=mx+b[/tex]

slope of given line = [tex]\frac{1}{2}[/tex]

slope of parallel line = slope of given line

Slope of parallel line = [tex]\frac{1}{2}[/tex]

Point slope form of a line is

[tex]y-y_1 = m(x-x_1)[/tex], point is (-3,2)

[tex]y+2=\frac{1}{2}(x+3)[/tex]

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