Respuesta :

Answer:

20

Step-by-step explanation:

using the definition of nPr = [tex]\frac{n!}{(n-r)!}[/tex]

where n! = n(n - 1)(n - 2).....× 3 × 2 × 1

5P2 = [tex]\frac{5!}{3!}[/tex] = [tex]\frac{5(4)(3)(2)(1)}{3(2)(1)}[/tex] = 5 × 4 = 20