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Solid sodium reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrogen gas are formed when 48.7 g of sodium are added to water? Show your work. (4 points) 2Na + 2H2O ---> 2NaOH + H2 2Na + 2H2O ---> 2NaOH + H2 48.7 g ? Molecules 2 mol Na= 1 mol H2 1 mol Na= 23g Na 1 mol H2= 6.02x1023 molecules (48.7g Na/1)x(1 mol Na/23g Na)x(1 mol H2/2mol Na)x(6.02x1023/1 mol H2) (48.7)(6.02x1023)/(23)(2)= 293.174x1023 molecules Can someone please tell me what I did wrong?

Respuesta :

Answer: Number of molecules of hydrogen gas [tex]6.32\times 10^{32}[/tex]

Explanation:

[tex]2Na+2H_2O\rightarrow 2NaOH+H_2[/tex]

Number of moles of sodium =[tex]\frac{\text{mass of sodium}}{\text{molar mass of sodium}}=\frac{48.7 g}{23 g/mol}=2.11mol [/tex]

According to reaction , 2 moles of sodium produces 1 mole of hydrogen gas , then 2.11 mol of sodium will= [tex]\frac{1}{2}\times 2.11 mol[/tex] of hydrogen gas that is 1.05 moles of hydrogen gas.

Number of molecules = [tex]N_A(\text{Avogadro number})\times [/tex] moles of substance

Moles of hydrogen gas formed = 1.05 moles

Number of molecules of hydrogen gas = [tex]N_A\times [/tex] moles of hydrogen gas

Number of molecules of hydrogen gas [tex]=6.022\times 10^{23} mole^{-1}\times 1.05 mole=6.32\times 10^{32}[/tex]

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