Respuesta :
[tex]\text{Answer: a) }x=0.95y[/tex]
[tex]b)\ x=3.76y[/tex]
[tex]c)\ x=1.05y[/tex]
[tex]d)\ k_2=1.11\times k_1[/tex]
Explanation:
Since we have given that
[tex]1\ quarts=0.95\ liters[/tex]
a) Write a direct variation equation that relates x quarts to y liters.
Since Direct variation can be written in the form :
[tex]\frac{x}{y}=k\\\\x=yk\\\\x=0.95y\\\\Here,\ k=0.95[/tex]
b) Write a direct variation equation that relates x gallons to y liters.
Since we have given that
[tex]1\ gallon=3.76\ liters[/tex]
Since Direct variation can be written in the form :
[tex]\frac{x}{y}=k\\\\x=yk\\\\x=3.76y\\\\Here,\ k=3.76[/tex]
c) Write a direct variation equation that relates x liters to y quarts.
Since we have given that
[tex]1\ liter=1.05\ quarts[/tex]
Since Direct variation can be written in the form :
[tex]\frac{x}{y}=k\\\\x=yk\\\\x=1.05y\\\\Here,\ k=1.05[/tex]
d) What is the relationship between the values of k in the direct variation equations in parts (a) and (c)?
[tex]\text{ let }k_1=0.95\text{ and }k_2=1.05\\\\k_2=1.11\times k_1[/tex]
