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An object accelerated from rest with a constant acceleration of 5.2 m/s^2, what will its velocity be after 3 s

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remotecontrolbrain

Answer: The velocity after 3 s will be [tex]15.6\frac{m}{s}[/tex]

Explanation:

Since the initial velocity v0 is zero:

[tex]v(t) = at + v_0 = at\\v(3) = 3a = 3\cdot5.2 \frac{s\cdot m}{s^2}= 15.6\frac{m}{s}\\[/tex]

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