Respuesta :

gmany

[tex]-\dfrac{3}{7}h=6\ \ \ \ |\cdot\left(-\dfrac{7}{3}\right)\\\\\left(-\dfrac{\not7^1}{\not3_1}\right)\cdot\left(-\dfrac{\not3^1}{\not7_1}\right)h=-\dfrac{7}{\not3_1}\cdot\not6^2\\\\h=-7\cdot2\\\\\boxed{h=-14}[/tex]