The function f(x) = x^2 - 2x - 8 is a quadratic function that has the x-intercepts of x = 4 and x = -2
How to determine the graph of the function?
The function is given as:
f(x) = x^2 - 2x - 8
Expand the function
f(x) = x^2 + 2x -4x - 8
Factorize the function
f(x) = x(x + 2) -4(x + 2)
Factor out x + 2
f(x) = (x -4)(x + 2)
Set to 0
(x -4)(x + 2) = 0
Solve for x
x = 4 or x = -2
This means that the function f(x) = x^2 - 2x - 8 is a quadratic function that has the x-intercepts of x = 4 and x = -2
See attachment for the graph of the function
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