The volume of nitrogen monoxide that occupy at STP is= 277 Ml
calculation The volume is obtained using the combined gas law that is P1V1/T1= P2V2? Where P1 = 720 MmHg V1 = 400ml T1= 100 +273= 373 K At STP temperature = 273 K and pressure= 760 mm hg therefore T2= 273 k p2 = 760 mmhg V2=? make V2 the subject of the formula
V2= (T2 ×P1 ×V1)/(P2×T1)
V2 is therefore = (273k x720 mmhg x 400 ml)/(760 mmhg x373K) = 277 Ml
