The work done by the force pushing the puck is equal to the product between the force and the distance covered:
[tex]W=Fd=(750 N)(2.0 m)=1500 J[/tex]
And the power is the work done per unit time:
[tex]P= \frac{W}{t} [/tex]
and using t=0.30 s, we find the power:
[tex]P= \frac{1500 J}{0.30 s}=5000 W [/tex]