A solution of 0.90 g of an unknown nonelectrolyte in 100 ml of water at 27◦c has an osmotic pressure of 0.55 atm. what is the molecular weight of this compound? (assume
Osmotic pressure is mathematically expressed as π = CRT where, C = concentration of solution R = gas constant = 0.082 atm mol-1 K-1 T = temperature = 300 K π = osmotic pressure = 0.55 atm
∴ 0.55 = C X 8.314 X 300 ∴C = 0.022 M
Now, conc of solution (in terms of molarity) = [tex] \frac{\text{weight of solute}}{\text{molecular weight X volume of solution(l)}} [/tex]
Given: weight of solute = 0.9 g volume of solution = 100 ml = 0.1 l
