Aarahlie Aarahlie 13-01-2023 Mathematics contestada 1. If [tex] \frac{(tanθ + tan30)}{(1- tanθ × tan30)} = - 1[/tex] find the value of tanθ2 Verify each of the followinga. [tex]sin^2θ - cos^2θ = (sinθ-cosθ)(1+sinθcosθ)[/tex]b. [tex] {cosecθ}^{2} - cosecθ = \frac{ {cot}^{2}θ }{(1+sinθ)} )\ \textless \ br /\ \textgreater \ [/tex]c. [tex] {(sinθ-cosθ)}^{2} + {(sinθ + cosθ)}^{2} = 2[/tex]d. [tex] \sqrt{ \frac{{(1 + {tan}^{2}θ } }{1 + {cot}^{2}θ } } = tanθ[/tex]e. [tex] \frac{cosθ - 1}{secθ + tanθ} + \frac{cosθ + 1}{secθ - tanθ} = 2(1 + tanθ)[/tex]